Lakers embark on long road trip
(Sports Network) – The Los Angeles Lakers are just 7-9 after 16 games in the
2005-06 campaign. With a losing record, the Lakers are set to begin a six-game
On Tuesday, the Lakers visit the Milwaukee Bucks at the Bradley Center. It
will be the first of two meetings between the clubs this season. The Lakers
are scheduled to host the Bucks on March 24, 2006 at the Staples Center.
The Lakers have won eight straight and 17 of the last 19 meetings against
Milwaukee. The last time the Bucks beat the Lakers was on March 21, 2001 in
front of their home crowd. LA has won four in a row and eight of its last nine
Los Angeles enters the road trip on a winning note. On Sunday, Kobe Bryant hit
two free throws with seven seconds remaining and finished with 29 points
overall to lift Los Angeles over the Charlotte Bobcats, 99-98, at the Staples
Center Chris Mihm scored a season-high 21 points and collected nine rebounds
in the victory over Charlotte for the Lakers, who have won two of their last
three games overall. Sasha Vujacic added 12 points off the bench in the win.
LA is 3-4 on the road this season. The Lakers will also visit Toronto,
Chicago, Minnesota, Dallas and Memphis on the current swing.
Bryant has played 40 or more minutes in five straight games and has scored at
least 20 points in all of the contests. He leads the Lakers in scoring (30.5
ppg) this season, and is averaging 30.7 points, 4.9 rebounds and 3.5 assists
in his last 10 contests.
The Lakers have scored more than 100 points in six games this season. They are
4-2 in those contests.